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6y^2-35y-4=0
a = 6; b = -35; c = -4;
Δ = b2-4ac
Δ = -352-4·6·(-4)
Δ = 1321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1321}}{2*6}=\frac{35-\sqrt{1321}}{12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1321}}{2*6}=\frac{35+\sqrt{1321}}{12} $
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